For the differential equation `(x^2y^2)dx2xy dy=0`, which of the following are true (A) solution is `x^2y^2=cx` (B) `x^2y^2=cx` `x^2y^2=xc` (D) `yClick here👆to get an answer to your question ️ The differential equation 2xy dy = x^2 y^2 1 dx determines Join / Login Question The differential equation 2 x y d y = x 2 y 2 1 d x determines A A family of circles with centre on xaxis B 2 x 2 d x d y − 2 x y y 2 = 0Expresiones semejantes (x^2y^2)dx 2xydy = 0 (x^2y^2)dx 2xydy = 0;
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X 2 y 2 dx 2xy dy 06-The equation 2xydy (x^2 y^2 1)dx =0 can be rewritten as dy/dx y/2x = (1x^2)/2xy which is a Bernoulli equation To reduce it to normal form take y = U (x)^1/2 Then y' = (1/2) (U^1/2)U'Q true or false If f is integrable over a, b and R b a f(x)dx = 0, then f(x) = 0 for all x ∈ a, b A According to the given information, it is required to tell whether the given statement is true or fa
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Share It On Facebook Twitter Email 1 Answer 1 vote answered by rubby (5k points) selected by Vikash Kumar Best answer Integrating both sides, we getY dy x sec(y /x) y (3) dx (4) ху dx x Find the general solution of the following differential equations dy sec y (1) (2) xy dx (1x ?)dy = 0 dx 1x?Q The curve satisfying the differential equation, $(x^2 y^2) dx 2xydy = 0$ and passing through the point $(1, 1)$ is
Given the equation $$x^{2} 2 x y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} y^{2}{\left(x \right)} = 0$$ Do replacement $$u{\left(x \right)} = \frac{ySolution for Which of the following equations is non homogeneous differential equation?Exercises Find the general solution of the following differential equations (1) (xy y2)dx – x'dy = 0) (2) (x ² y ²)dx 2xydy = 0) dy _y?
O a (x² – 2y²)dx 2xydy = 0 O b dy y²2zy zp O (y Vr² y²)d¤ = rdy (x 2 y 2 ) dx 2xy dy = 0 given that y = 1 when x = 1 differential equations;Identical expressions (x^ two y^ two)dx 2xydy= zero (x squared plus y squared )dx minus 2xydy equally 0 (x to the power of two plus y to the power of two)dx minus 2xydy equally zero (x2 y2)dx 2xydy=0 (x to the power of 2 y to the power of 2)dx 2xydy=0
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Answer Given, (x2 y2)dx−2xydy = 0 ⇒ (x2 y2)dx= 2xydy ⇒ dxdySolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more(x al cuadrado más y al cuadrado )dx más 2xydy es igual a 0 (x en el grado dos más y en el grado dos)dx más 2xydy es igual a cero (x2y2)dx2xydy=0 (x en el grado 2y en el grado 2)dx2xydy=0 (x^2y^2)dx2xydy=O;
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We want to find the interval for a unique solution using the Picard–Lindelöf theorem given \frac {dy} {dx}=x^ {2}y^ {2}, y (0)=0 In this case, x_0 = y_0 = 0 For some a, b , the function f (x, y) = x^2 y^2 = x2 y2,y(0)= 0 In this case, x0 = 0We have D (xy^2) = 2x Integrate each side with respect to x to get xy^2 = x^2 C (constant of integration) We will assume we are on the interval (0, infinity) here, so x > 0 Divide by x to get y^2 =x C/x, which gives an implicit form of the general solution on (0, infinity) This isSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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x 2 d x − y 2 d x x d y 2 = 0 d x x d y 2 − y 2 d x x 2 = 0 d x d ( y 2 x) = 0 x y 2 x = C It seems to me that there is a sign mistake somewhere Share edited Nov 11 ' at 2301 answered Nov 11 ' at 2256 Aryadeva Solve (y√(x^2y^2))dxxdy=0 Latest Problem Solving in Differential Equations More Questions in Differential Equations Online Questions and Answers in Differential EquationsStack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange
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Question Solve The Initial Value Problem (x^23y^2)dx2xydy=0;y(2)=6 This question hasn't been answered yet Ask an expert Solve the initial value problem (x^23y^2)dx2xydy=0;y(2)=6Question No 1 The integrating factor of the differential equation (x 2 y 2)dx−2xydy=0 is Select one a x 2 y 2 b 1/x 2 c 1/y 2 d none of these Question2 Which of the following differential equation is non exact Select oneThe ODE is homogeneous ODE of order one This is because the coefficients of dx and dy are both homogeneous two variables functions of the same order I suggest you write the ODE as y′ = 32t2t2−t−2 = f (t), (x = 0,t = y/x) Find the solution of (xy^22x^2y^3)dx (x^2yx^3y^2)dy=0
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Divide the equation by x 2 x^2 x 2 y x ⋅ d y d x = 4 2 y 2 x 2 (1) \dfrac {y} {x} \cdot \dfrac {dy} {dx} = 4 2 \dfrac {y^2} {x^2} \tag {1} x y ⋅ d x d y = 4 2 x 2 y 2 ( 1) So, a sensible substitution is u = y x y = u x d y d x = x d u d x u u = \dfrac {y} {x} \Longrightarrow y = ux \Longrightarrow \dfrac {dy} {dx} = x \dfrac {du} {dx} u u = x y y = ux d x d y = x d x d u u $(x^2y^2)dx−2xydy=0$ $\frac{dy}{dx}=\frac{x^2y^2}{2xy} $(i) This is a homogeneous differential equation because it has homogeneous functions of same degree 2 homogeneous functions are $(x^2y^2)$ and $2xy$, both functions have degree 2 Solution of differential equation Equation (i) can be written as,Dr/r = da*sec (a)* 1 tan ( Continue Reading (x^2 y^2)*dx 2*x*y*dy = 0 Go to polar coordinates x = r*cos (a), dx = cos (a)*dr r*sin (a)*da y = r*sin (a), dy = sin (a)*dr r*cos (a)*da Your equation now becomes cos (a)*dr r*sin (a)*da = cos (a)*sin (a)* (sin (a)*dr r*cos (a)*da
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Reshenie Differencialnoe Uravnenie X 2 2y 2 Dx 2xydy 0 Ucheba I Nauka
Solution for (x^2y^2)*dx2xy*dy=0 equation Simplifying (x 2 y 2) * dx 2xy * dy = 0 Reorder the terms for easier multiplication dx(x 2 y 2) 2xy * dy = 0 (x 2 * dx y 2 * dx) 2xy * dy = 0 Reorder the terms (dxy 2 dx 3) 2xy * dy = 0 (dxy 2 dx 3) 2xy * dy = 0 Multiply xy * dy dxy 2 dx 3 2dxy 2 = 0 Reorder the terms dxy 2 2dxy 2 dx 3 = 0 Combine like terms dxy 2 2dxy 2 = 1dxy 21dxy 2 dx 3 = 0 Solving 1dxy 2 dx 3 = 0Move all terms containing d to the left, all other terms to the right Factor out the Greatest Common Factor (GCF), 'dx' dx(5y 2 x 2) = 0 Subproblem 1 Set the factor 'dx' equal to zero and attempt to solve Simplifying dx = 0 Solving dx = 0 Move all terms containing d to Ex 95, 4 show that the given differential equation is homogeneous and solve each of them ( ^2 ^2 ) 2 =0 Step 1 Find / ( ^2 ^2 ) 2 =0 2xy dy = ( ^2 ^2 ) dx 2xy dy = ( ^2 ^2 ) dx / = ( ^2 ^2)/2 Step 2 Putting F (x, y) = / and finding F ( x, y) F (x, y) = ( ^2 ^2)/2 F ( x, y) = ( ( )^2 ( )^2)/ (2 )= ( ^2 ^2 ^2 ^2)/ ( ^22 )= ( ^2 ( ^2 ^2))/ ( ^22 ) = ( ^2 ^2)/2 = F (x, y) F ( x, y) = F (x, y) = F (x, y) Hence, F (x, y
2
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Solution of the differential equation `(x^(2)y^(2))dx2xy dy=0` isExercise 2 Standard form (y2 −2x)dx2xydy = 0 Exact if ∂P ∂y = ∂Q ∂x, where P(x,y) = y2 −2x Q(x,y) = 2xy ∂P ∂y = 2y = ∂Q ∂x ie ode is exact ∴ u(x,y) exists such that du = ∂u ∂x dx ∂u ∂y dy = P dxQdy = 0, giving i) ∂u ∂x = y 2 −2x , ii) ∂y = 2xy Integrate i) u = xy 2−x φ(y (x 2 y 2)dx 2xydy = 0 ⇒ the given differential equation is a homogenous equation The solution of the given differential equation is Put y = vx Integrating both the sides we get Resubstituting the value of y = vx we get x 2 y 2 = cx
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(x 2 y 2)dx 2xydy = 0 (x 2 y 2) dx = 2xydy `dy/dx = (x^2 y^2)/(2xy)`(i) The equation is a homogeneous equation Let y= vx, Differentiat ing wrt x, we get, `dy/dx=vx(dv)/dx`Factor out the Greatest Common Factor (GCF), 'dx' dx(y 2 2xy x 2) = 0 Factor a trinomial dx((y x)(y x)) = 0 Subproblem 1 Set the factor 'dx' equal to zero and attempt to solve Simplifying dx = 0 Solving dx = 0 Move all terms containing d to the left, all other terms to the right Simplifying dx = 0 The solution to this equation couldExpresiones semejantes (x^2y^2)dx2xydy=0 (x^2y^2)dx2xydy=0;
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(x 2 y 2)dx 2xy dy = 0 ∴ 2xy dy = (x 2 y 2)dx ∴ `"dy"/"dx" = ("x"^2 "y"^2)/"2xy"` (1) Put y = vx ∴ `"dy"/"dx" = "v x"du"/"dx"` ∴ (1) becomes, v x`"du"/"dx" = ("x"^2 "v"^2"x"^2)/("2x"("vx"))` ∴ `"v x""du"/"dx" = (1 "v"^2)/"2v"` ∴ `"x""dv"/"dx" = (1 "v"^2)/"2v" v = (1 "v"^2 2"v"^2 (4xy 3y2 – x) dx x(x 2y) dy = 0 4xydx3y²dxxdxx²dy2xydy=0 I dont know how to group to form integrable combination Jomo Elite Member Joined Messages 10,731 (4xy3y²x)dx x(x2y)dy=0 Can anyone show step by step solution by using inspection method Ill already solve it by integrating factorThe differential equation is given as (x2y2)dx2xydy = 0 ( x 2 y 2) d x 2 x y d y = 0 and y(3) = 1 y ( 3) = 1 Rewrit See full answer below
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The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction dx^ {2}\left (dy^ {2}\right)x=0 d x 2 ( − d y 2) x = 0 This equation is in standard form ax^ {2}bxc=0 Substitute d for a, y^ {2}d for b, and 0 for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Solve the differential equation `(x^2y^2)dx2xydy=0` The GS is y^2 = (A x^4)/(2x^2) Or, alternatively y = sqrt(A x^4)/(sqrt(2)x) We have (x^2 y^2) \\ dx xy \\ dy = 0 Which we can write in standard form as dy/dx = (x^2 y^2)/(xy) 1 Which is a nonseparable First Order Ordinary Differential Equation A suggestive substitution would be to perform a substitution of the form y = xv => dy/dx = v xv' \\ \\ \\ where v=v(x
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(x^ dos y^ dos)dx 2xydy = cero (x al cuadrado más y al cuadrado )dx menos 2xydy es igual a 0 (x en el grado dos más y en el grado dos)dx menos 2xydy es igual a cero (x2y2)dx 2xydy = 0 (x en el grado 2y en el grado 2)dx 2xydy = 0;2 minutes ago English Primary School answered Please help to do the target Can anyone subscribe my channel I can mark brainleast and give thanks but you have to really subscribe, and prove it, I will check if you do subscribe then I will mark brainleast, if you do subscribe I need 95 subscribers please it is studying channel and channelView this answer Given 2xy dx(x2−1) dy = 0 2 x y d x ( x 2 − 1) d y = 0 Rewrite 2xy dxx2 dy−1 dy = 0 2 x y d x x 2 d y − 1 d y = 0 Change the sides $$2 xy \ dx x^2 \ dy = 1
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